libooc/example/dog.c

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/*
* This file is part of libooc.
* https://xw3.org/hanez/libooc
*
* Copyright 2026 Johannes Findeisen <you@hanez.org>
* Licensed under the terms of the Apache-2.0 license.
* https://opensource.org/license/apache-2-0
*/
/*
* Dog -- an Animal subclass that overrides the virtual `speak` method.
*
* Because Dog embeds an Animal as its first member, a Dog can be passed
* wherever an Animal is expected and still reach Dog's own vtable.
*
* Subclassing here means three things, and this file shows each one. The object
* is allocated from Dog_class, whose `super` points at Animal_class so the
* inherited fields resolve. Animal's members are built by animal_init(), the
* base class' own entry point, rather than duplicated. And a separate vtable
* and destructor are registered for Dog, so the override and the extra
* allocation are cleaned up by the runtime type of the object.
*/
#include "dog.h"
#include <stddef.h>
#include <stdio.h>
#include <stdint.h>
#include <stdlib.h>
#include <string.h>
/*
* Copy `text` onto the heap; the caller owns the result.
*
* A private copy of Animal's helper, and identical to it. It is duplicated
* rather than shared because a class keeps its own constructor state: exposing
* dupstr() would mean the derived class reaching into a base class' internals
* to build its members, which is the coupling subclassing is meant to remove.
*
* Returns NULL if `text` is NULL or the allocation fails.
*/
static char *dupstr(const char *text)
{
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size_t len;
char *copy;
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if (!text)
return NULL;
len = strlen(text);
if (len == SIZE_MAX)
return NULL;
++len;
copy = malloc(len);
if (copy)
memcpy(copy, text, len);
return copy;
}
/*
* Virtual destructor: releases everything dog_new() allocated.
*
* This replaces Animal's destructor rather than running after it, because the
* library calls the one belonging to the object's runtime type and stops
* there. So a Dog is responsible for Animal's members too: `name` is freed
* below even though animal_init() allocated it, and Animal's own destroy()
* never runs for a Dog. The second free is the half of a derived destructor
* that is easy to forget.
*
* The order does not matter, since the two allocations are independent, and
* both are owned: "breed" is marked as owned in the field table, and "name" is
* marked as owned in Animal's, so ooc_set() releases a string when it replaces
* one and what is left here is freed on destruction.
*/
static void destroy(ooc_object *object)
{
Dog *dog = (Dog *)object;
free(dog->breed);
free(dog->animal.name);
}
/*
* Dog's implementation of AnimalVTable::speak.
*
* The signature is Animal's, not Dog's: a vtable entry is called through the
* base class' type, so the implementation casts its parameter back down. That
* cast is the cost of a subclass adding behaviour to an existing method, and
* it is safe only because Animal is the first member of Dog, which makes the
* two addresses the same.
*
* Adding a *new* virtual method is not possible this way, since the vtable is
* the base class' struct: that takes an interface struct of its own, holding
* the vtable pointer this class already has as `vtable`.
*/
static void speak(Animal *animal)
{
Dog *dog = (Dog *)animal;
printf("%s says: Woof! (%s)\n", dog->animal.name ? dog->animal.name : "(unnamed)",
dog->breed ? dog->breed : "(unknown breed)");
}
/*
* Dog's own vtable, identical in shape to Animal's and holding Dog's speak.
*
* A subclass that overrides nothing reuses the base table as it is, so the
* override is what makes a separate table necessary here.
*/
static const AnimalVTable vt = {
.speak = speak,
};
/*
* The fields Dog adds on top of the ones Animal publishes.
*
* A derived class lists only what it declares itself; the rest is inherited
* rather than repeated. Anything missing here -- "name", "age", and Animal's
* two underscore names -- is still reachable through ooc_get() and ooc_set(),
* because Dog_class names Animal_class as its base and lookup walks the chain.
*
* Like Animal's name, `breed` is marked as owned, so replacing it through
* ooc_set() releases the string it held before. The underscores of the
* inherited fields keep their meaning across the boundary: ooc_set(dog, "_id")
* is still refused even though Dog did not declare it.
*/
static const ooc_field Dog_fields[] = {
{ "breed", offsetof(Dog, breed), sizeof(((Dog *)0)->breed), 1 },
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{ NULL, 0, 0, 0 },
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};
/*
* Dog's runtime type record.
*
* `super` is what makes Dog a Dog: field lookup continues from Animal_class, so
* "name", "age", "_id" and "__legs" resolve even though Dog does not list them.
* `size` is sizeof(Dog) rather than sizeof(Animal), since the allocation has to
* hold the breed as well as the base.
*/
const ooc_class Dog_class = {
.size = sizeof(Dog),
.destroy = destroy,
.super = &Animal_class,
.fields = Dog_fields,
};
/*
* Initialise the members Dog owns, leaving the object ready to speak as a Dog.
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*
* Split out of dog_new() so a subclass of Dog can build this part itself, the
* same reason animal_init() exists for Animal. Snoopy does exactly that: it
* calls this, then installs its own vtable and adds its own members.
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*
* The vtable is overwritten after animal_init() rather than before, since that
* call installs Animal's table and this one has to win.
*
* The breed is copied before the base part is built, so a failed copy cannot
* leave a half-initialised object behind: on failure nothing has been written
* at all and the caller may simply release the zeroed storage. Failure leaves
* the dog unchanged.
*
* Returns 0, or -1 for a NULL dog, an already initialised one, or a failed copy.
* Requires zero-initialised members and external synchronization between
* constructors in different threads.
*/
int dog_init(Dog *dog, const char *name, int age, const char *breed)
{
char *copy;
if (!dog || dog->breed || dog->animal.vtable)
return -1;
copy = dupstr(breed);
if (!copy)
return -1;
if (animal_init(&dog->animal, name, age) != 0) {
free(copy);
return -1;
}
dog->breed = copy;
dog->animal.vtable = &vt;
return 0;
}
/*
* Create a Dog named `name` of the given `breed` and return it, or NULL.
*
* Two steps: allocate through ooc_new() with a reference count of one, so the
* caller owns the result and must release it, and then let dog_init() build the
* members. The allocation carries Dog's destructor from the start, so a failed
* dog_init() releases cleanly: nothing was written, and free(NULL) is what the
* destructor finds.
*
* Returns NULL if the allocation fails or dog_init() refuses, in both cases
* leaving nothing to release.
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*/
Dog *dog_new(const char *name, int age, const char *breed)
{
Dog *dog = ooc_new(&Dog_class);
if (!dog)
return NULL;
if (dog_init(dog, name, age, breed) != 0) {
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ooc_release(dog);
return NULL;
}
return dog;
}